Jersey #10 Posted December 20, 2011 Posted December 20, 2011 geek or not, you don't have to start splitting atoms for simple equations. anyway here is the answer.. 2 = 6/3 = 4/3 + 2/3 = 1.333... + 0.666...= 1.999... 4/3 + 2/3 does not actually equal to 1.333... + 0.666.. it's approximately equal to that. 2>1.99999999999999999999999999999999999999999999999999999999999999 ps - I'm assuming that your explaination would have explained 2 = 1.99 there is only one case where a mathematically higher number is smaller than a mathematically lower number.
Jersey #10 Posted December 20, 2011 Posted December 20, 2011 x = .9... 10x = 9.9... 9x = 9 x = 1 9x = 8.1:giggle:
akshayxyz Posted December 20, 2011 Author Posted December 20, 2011 4/3 + 2/3 does not actually equal to 1.333... + 0.666.. it's approximately equal to that. 0.666 can be rounded to 0.67, in that case 1.33 + 0.67 = 2.0 2>1.99999999999999999999999999999999999999999999999999999999999999 Lol @ bolded part. 4/3 = 1.333... by definition. and so is 2/3 = 0.666... and the proof you have given - by rounding off - is simply wrong. Another proof is 1/9 = 0.111... Multiply both sides by 9, 1 = 0.999... which is equivalent to 2 = 1.999... w/o a doubt 2 > 1.9999999999999999999 (i.e. if there are countably finite number of 9s after the decimal)... but if its infinitely repeating, that is '9' repeats forever, then "2 = 1.999...", by convention "..." represent infinitely repeating digits, or you can put a bar over the repeating decimal, that I could not figure out how to do in this editor.
yoda Posted December 20, 2011 Posted December 20, 2011 9x = 8.1:giggle: 9x = 9.9... - .9... 9x = 9 8.1?
akshayxyz Posted December 20, 2011 Author Posted December 20, 2011 x = .9... 10x = 9.9... 9x = 9 x = 1 9x = 8.1:giggle: transparent, you have lost it ... yoda is right. Subtracting 1st equation from second. 9x = 9.
yoda Posted December 20, 2011 Posted December 20, 2011 http://en.wikipedia.org/wiki/0.999... In the last few decades, researchers of mathematics education have studied the reception of this equality among students, many of whom initially question or reject it. Didn't know this is a researched subject. The one I listed was a simple set of equations we were either taught or came across during school days.
punjabi_khota Posted December 20, 2011 Posted December 20, 2011 UVA ka naam barbaad kar raha hai :icflove:
akshayxyz Posted December 20, 2011 Author Posted December 20, 2011 haha.. g92, edited pretty soon :)..
The Outsider Posted December 20, 2011 Posted December 20, 2011 UVA ka naam barbaad kar raha hai :icflove: He has single handedly convinced me to reject any job applications I get from UVA Engineering graduates.:giggle:
Jersey #10 Posted December 21, 2011 Posted December 21, 2011 I know it's down in the text books and an accepted concept. the 9x=8.1 was a pun which most didn't get but that's fine. If you go back to that post, you may get it. so let's say 2 = 1.999...(and considering infinity doesn't end or repeats) 2 = 1.999... is eventually incorrect but approximately true. There is always that small amount that's missing in the 1.999... to equal to 2. If you were to look at a graph, it would infinitely approach 2 but would never actually reach it. In correct terms, 1.999... = (2 - 1/n), n -> infinity n will continuously approach the limit (0), in different words (2 - 1/n) approaches 2 for arbitrarily large n. In mathematical terms, (2 - 1/n -> 2 as n -> infinity). The definition of a limit: For any |1/n - 0| arbitrarily close to 0, there exists such an n, arbitrarily close ~= as close as you like
akshayxyz Posted December 21, 2011 Author Posted December 21, 2011 I know it's down in the text books and an accepted concept. the 9x=8.1 was a pun which most didn't get but that's fine. If you go back to that post, you may get it. so let's say 2 = 1.999...(and considering infinity doesn't end or repeats) 2 = 1.999... is eventually incorrect but approximately true. There is always that small amount that's missing in the 1.999... to equal to 2. If you were to look at a graph, it would infinitely approach 2 but would never actually reach it. In correct terms, 1.999... = (2 - 1/n), n -> infinity n will continuously approach the limit (0), in different words (2 - 1/n) approaches 2 for arbitrarily large n. In mathematical terms, (2 - 1/n -> 2 as n -> infinity). The definition of a limit: For any |1/n - 0| arbitrarily close to 0, there exists such an n, arbitrarily close ~= as close as you like And yet you want to contend it with your own interpretation? I do not have anything further to say. (Say thanks, that I did not resort to smilies and other type of language, that has become norm here).. This concept is as clearly defined as 2+2 = 4. So if you still want to argue on this, you can imagine how it will be perceived like.
mishra Posted December 21, 2011 Posted December 21, 2011 Where is the error in bolow equaltion, if any
CSK Fan Posted December 21, 2011 Posted December 21, 2011 Where is the error in bolow equaltion, if any If no study = fail then study = fail/no
mishra Posted December 21, 2011 Posted December 21, 2011 Consider there is implicit yes with "Yes = +1" Replace value "No =-1" (No+1)= (-1+1)
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